7x/4x^2=7/8

Solution for 7x/4x^2=7/8 equation:

7x/4x^2=7/8

We move all terms to the left:

7x/4x^2-(7/8)=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

7x/4x^2-(+7/8)=0

We get rid of parentheses

7x/4x^2-7/8=0

We calculate fractions


(-28x^2)/32x^2+56x/32x^2=0

We multiply all the terms by the denominator


(-28x^2)+56x=0

We get rid of parentheses

-28x^2+56x=0

a = -28; b = 56; c = 0;
Δ = b2-4ac
Δ = 562-4·(-28)·0
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-56}{2*-28}=\frac{-112}{-56}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+56}{2*-28}=\frac{0}{-56}
=0
$